When the valve between the 2.00-L bulb, in which the gas pressure is 2.00 atm, and the 3.00-L bulb, in which the gas pressure is 4.00 atm, is opened, what will be the final pressure in the two bulbs

Explanation:

Let assume that gases inside bulbs behave as an ideal gas and have the same temperature. Then, conditions of gases before and after valve opened are now modelled:

Bulb A (2 L, 2 atm) - Before opening:

Bulb B (3 L, 4 atm) - Before opening:

Bulbs A & B (5 L) - After opening:

After some algebraic manipulation, a formula for final pressure is derived:

And final pressure is obtained:

i think the answer is a and b

i wish you luck