A tugboat tows a ship with a constant force of magnitude F1. The increase in the ship's speed during a 10 s interval is 3.0 km/h. When a second tugboat applies an additional constant force of magnitude F2 in the same direction, the speed increases by 11 km/h during a 10 s interval. How do the magnitudes of F1 and F2 compare? (Neglect the effects of water resistance and air resistance.)

The magnitude of F₁ is 3.7 times of F₂

Explanation:

Given that,

Time = 10 sec

Speed = 3.0 km/h

Speed of second tugboat = 11 km/h

We need to calculate the speed

The force F₁is constant acceleration is also a constant.

We need to calculate the acceleration

Using formula of acceleration

Similarly,

For total force,

The speed of second tugboat is

We need to calculate total acceleration

We need to calculate the acceleration a₂

We need to calculate the factor of F₁ and F₂

Dividing force F₁ by F₂

Hence, The magnitude of F₁ is 3.7 times of F₂

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