What is the phase angle of an AC series circuit that is constructed of a 14.5-Ω resistor along with 16.5-Ω inductive reactance and 9.41-Ω capacitive reactance?

26.06°

Given an RLC circuit [a circuit containing a capacitor, inductor and resistor], the phase angle (Φ), which is the difference in phase between the voltage and the current in the circuit, is given by;

Φ = tan⁻¹ [ ]            --------------------------(i)

Where;

= inductive reactance of the circuit

= capacitive reactance of the circuit

R = resistance of the circuit

From the question;

= 16.5 Ω

= 9.41 Ω

R = 14.5 Ω

Substitute these values into equation (i) as follows;

Φ = tan⁻¹ [ ]    

Φ = tan⁻¹ [ ]

Φ = tan⁻¹ [ 0.4890]

Φ =  26.06°

Therefore the phase angle of the AC series circuit is 26.06°

the answer is the first electromagnet (a). this is because it has more coils around the ferromagnetic material. increasing the number of coils increases the surface area in which the metal interacts with the current in the coil. this enables more atoms in the metal to become aligned hence becoming more magnetized.