Two large metal plates are separated by 2.67 cm. One plate has a negative charge, and the other plate has a positive charge. The negative plate is heated until an electron barely comes loose from its surface. The electron then accelerates between the plates and strikes the positive plate moving at a speed of 1.32x107 m/s. What is the voltage between the plates

voltage between the plates is 4.952 × V

Explanation:

given data

plate separated distance = 2.67 cm

electron speed = 1.32 ×  m/s

solution

we will get here first force that is express as

force in parallel plate F =   ..............1

and force by Newton second law F = ma   .............2

equate equation 1 and 2

ma =    .................3

and here we know as kinematic equation

v²- u² = 2 × a × s    ...........4

so for initial speed acceleration will be

a =  

a =  

a = 3.262 ×  m/s²

now we put a in equation 3 and we get v

ma =

9.1093 × × 3.262 ×  =  

solve it we get

v = 4.952 × V

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