Physics, 04.03.2020 03:57 bvallinab

The lowest-pitch tone to resonate in a pipe of length l that is closed at one end and open at the other end is 200 hz. Which frequencies will not resonate in the same pipe?

Answers: 3

Show answers

Answers

Answer from: MZ2017

The frequency 400 hz is not possible .

Explanation:

Given that,

Frequency = 200 hz

Length = l

Suppose, The given frequencies are,

600 Hz, 1000 Hz, 1400 Hz, 1800 Hz and 400 hz.

The possible resonance frequencies are

We need to calculate the fundamental frequency

Using formula of fundamental frequency for pipe

$F=\dfrac{nv}{4L}$

Where, n = odd number

Put the value of frequency

$200= \dfrac{nv}{4L}$

We need to calculate the first over tone

Using formula of fundamental frequency

n = 3,

$F=\dfrac{nv}{4L}$

Put the value into the formula

$F_{2}=3\times\dfrac{v}{4l}$

$F_{2}=3\times200$

$F_{2}=600\ Hz$

We need to calculate the second over tone

Using formula of fundamental frequency

n = 5,

$F=\dfrac{nv}{4L}$

Put the value into the formula

$F_{3}=5\times200$

$F_{3}=1000\ Hz$

We need to calculate the third over tone

Using formula of fundamental frequency

n = 7,

$F=\dfrac{nv}{4L}$

Put the value into the formula

$F_{4}=7\times200$

$F_{4}=1400\ Hz$

We need to calculate the fourth over tone

Using formula of fundamental frequency

n = 9,

$F=\dfrac{nv}{4L}$

Put the value into the formula

$F_{5}=9\times200$

$F_{5}=1800\ Hz$

Hence, The frequency 400 hz is not possible .

Answer from: Quest

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.

Answer from: Quest

Iwould have to say sorry i can't elaborate more. hope this though!

Another question on Physics

Physics, 22.06.2019 00:30

Two vectors are shown. which statement best compares the vectors? vector x has greater magnitude than vector y. vector y has greater magnitude than vector x. the vectors have the same displacement. the vectors have the same direction.

Answers: 1

Answer

Physics, 22.06.2019 09:00

The material that keeps its new shape after it is stretched is called?

Answers: 1

Answer

Physics, 22.06.2019 11:00

If angle "a" is 25°, angle "b" is: a) equal to angle c b) less than angle c c) greater than angle c

Answers: 1

Answer

Physics, 22.06.2019 19:30

Refrigerant-134a flows through a carnot heat pump cycle at 0.5 kg/s. it is known that the maximum absolute temperature in the cycle is 1.1 times the minimum absolute temperature, and the net power input to the cycle is 2.5 kw. if the refrigerant changes from a saturated vapor to a saturated liquid during the heat rejection process, determine the maximum magnitude of the enthalpy of vaporization for this process in kj/kg (with 3 significant figures).

Answers: 3

Answer

You know the right answer?

The lowest-pitch tone to resonate in a pipe of length l that is closed at one end and open at the ot...

Questions

Physics, 18.03.2021 03:00

Explain how sedimentary rock is formed....