. A proton, which moves perpendicular to a magnetic field of 1.2 T in a circular path of radius 0.080 m, has what speed? (qp = 1.6 · 10-19 C and mp = 1.67 · 10-27 kg)

Explanation:

We are given that

Magnetic field, B=1.2 T

Radius of circular path, r=0.080 m

We have to find the speed of proton.

We know that

Magnetic force, F=

According to question

Magnetic force=Centripetal force

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explanation:

need to see circuit to get time constant