Suppose you hit a 0.058-kg tennis ball so that the ball then moves with an acceleration of 10 m/s2. If you were to hit a basketball of mass 0.58 kg with the same force, what would the acceleration a of the basketball be?

1 m/s²

Explanation:

Force = mass × acceleration

F = ma Equation 1

Where F = force, m = mass, a = acceleration.

Given: m = 0.058 kg, a = 10 m/s²

Substitute into equation 1

F = 0.058(10)

F = 0.58 N.

If the same force was used to hit the baseball,

F = m'a

a = F/m' Equation 2

Where M' = mass of the baseball.

Given: F = 0.58 N, m' = 0.58 kg.

Substitute into equation 2

a = 0.58/0.58

a = 1 m/s²

1 m/s^2.

Explanation:

Note:

Force = mass x acceleration. 

Given:

mass = 0.058 kg

acceleration = 10 m/s2

Therefore, force = 0.058 x 10

= 0.58 N.

Since the same force is to be used, this same value is used for the other condition.

mass = 0.58 kg

Force = 0.58 N

F = m × a

a = 0.58/0.58

= 1 m/s^2.

a

explanation:

no diagram was provided, but i'm guessing it's the one i've attached to my answer.

here, a mechanical force turns the rod.   this generates an electric current in the coil, which powers the bulb.

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