It is known that the electric force of repulsion between two electrons is much stronger than the gravitational attraction. For two electrons at a distance d apart, calculate the ratio of the size of the electrostatic repulsion to that of the gravitational attraction. Use the following data: k = 8.99x10^9 Nm2/C2, e = 1.60x10^-19 C, G = 6.67x10^-11 Nm2/kg2, me = 9.11x10^-31 kg.

348.22*10^(-104)

Explanation: gravitational force between electrons is gotten using formulae below

Fg = G ×me×me/d²

Fg = gravitational force

G = gravitational constant = 6.67x10^-11 Nm2/kg2

me = mass of electron = 9.11×10^-31 kg

d = distance between electrons

Fg = (6.67x10^-11 × 9.11×10^-31 ×9.11×10^-31) / d²

Fg = 64.04*10^(-72) /d²

Fe = k×e ×e/d²

Where Fe = strength of electric field

K = electric constant = 8.99x10^9 Nm²/C²

e = 1.60x10^-19 C

Fe = 8.99x10^9 × 1.60x10^-19 × 1.60x10^-19/d²

Fe =2.23*10^(-28)/ d²

We are to find Fe/ Fg

=2.23*10^(-28)/ d² ÷ 64.04*10^(-72) /d²

=2.23*10^(-28)/ d² × d²/64.04*10^(-72)

= 2.23*10^(-28)/ 64.04*10^(-72)

= 348.22*10^(-104)

the answer is 12 as i may remember

: )