A student performs an experiment that produces 5.78 grams of silver chloride. He calculated that 7.25 grams of silver chloride should have precipitated if all of the limiting reactant reacted. What is his percent yield?

79.7%

Explanation:

Given:

Actual yield obtained by the student on performing the experiment is 5.78 g.

Theoretical yield calculated by the student is 7.25 g.

Now, the percent yield of silver chloride is given as the ratio of actual yield to theoretical yield expressed a percentage.

So, the percent yield is given as:

Plug in the given values and solve for the percent yield. This gives,

Therefore, the percent yield is 79.7%.

1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//

inverse v=i*r

nice nice