A voltaic cell with Mn/Mn2+ and Cd/Cd2+ half-cells has the following initial concentrations: [Mn2+]= 0.090 M; [Cd2+] = 0.060 M. (a) What is the initial E cell ?

Initial Ecell = 0.78V

Explanation:

From the question, we get;

(Cd)2+) + Mn ---> Cd + (Mn2+)

We will check half cell potentials from the table attached, we get ;

Mn = - 1.18V and Cd = - 0.4V

Ecell (standard) = E(reduction) - E(oxidation) = - 0.4 - (-1.18) = 0.78V

what type of charge does it have? negative

overcharge is the right answer system