A source emits sound uniformly in all directions. A radial line is drawn from this source. On this line, determine the positions of two points, 0.94 m apart, such that the intensity level at one point is 2.12 dB greater than the intensity level at the other. (Enter your answers from smallest to largest.)

Positions of two points are : 3.4 m and 4.3 m.

Explanation:

Let two distance be r and r+0.94.

Now intensity at r, =  

intensity at (r+0.94), =  

Now for decibel,

= 10 log ()

= 10 log ()

As given on question:

                                      - = 2.12 dB

                               ⇒ 2.12 dB = 10 log () - 10 log ()

                              ⇒0.212 = log ()

                              ⇒ =

                              ⇒ =

                              ⇒      =

                               ⇒ r= 3.4 m,    r+0.94= 4.3 m

Hence the position of two points is 3.4 m and 4.3 m.

the rearrangement of particles in a physical change. hope this

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