Two blocks are connected by a massless rope that passes over a 2 kg pulley with a radius of 5 cm. The rope moves over the pulley without slipping. The mass of block A is 2 kg and the mass of block B is 3 kg. Block A is also connected to a horizontally-mounted spring with a spring constant of 150 J/m2. What is the period (in s) of simple harmonic oscillations of this system?

Answer the radiant sun;

Answer: 1.4 seconds which is the third optionexplanation: current is defined as the flow of charge per timetherefore, the equation that relates current, charge and time can be expressed as follows: i = δq / δtwhere: i is the current given = 1.8 ampereδq is the charge given = 2.5 coulombδt is the time required for the flow of the given charges to give the 1.8 ampere.substitute with the givens in the above equation to get the time as follows: 1.8 = 2.5 / δtδt = 2.5 / 1.8 = 1.38888 which is approximately 1.4 secondshope this was !