Consider a ray of light that propagates from water (n=1.33) to air (n=1). If the incident ray strikes the water-air interface at an angle θ1≠0, which of the following relations regarding the angle of refraction, θ2, is correct?

a. θ2>θ1
b. θ2<θ1
c. θ2=θ1

will be greater.  

Explanation:

Given :

Refractive index of water = 1.33 .

Refractive index of air = 1 .

are angle from normal.

The ray of light strikes at the water-air interface at an angle .

We know , when light travels from denser medium to rarer medium its bends away from the normal.

Since , its bends away from the normal.

Therefore , will be greater.  

Hence, this is the required solution.