A roller coaster with people on board has a total mass of 4500 kg and starts at a height of 22 meters with a speed of 2.0 m/s. 50 kJ of work is done by friction on the way to the bottom of the ride. What is the speed at the bottom of the ride?

Explanation:

Energy at the bottom

= 1/2 mu² + mgh - work done by friction

= 1/2 x 4500 x 2² + 4500 x 9.8 x 22 - 50000

= 9000+970200 - 50000

= 929200 J

1/2 m  V² = 929200

V = 20.32 m /s

trig 15.3 cos

the chart show the masses and velocities of two colliding objects that stick together after a collision.

according to the law of conservation of momentum, the momentum of the object after the collision is  

answer

1,500

kg • m/s.