What must the charge (sign and magnitude) of a particle of mass 1.43 gg be for it to remain stationary when placed in a downward-directed electric field of magnitude 660 N/CN/C

The charge is 21.2μC

Explanation:

Given that,

Mass = 1.43 g

Electric field = 660 N/C

We need to calculate the charge

Using formula of force

Put the value into the formula

Hence, The charge is 21.2μC

grav force prop 1/r squared 2r all squared is 4rsquared 1/4rsquared quartered

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards