A plane flies towards a ground-based radar dish. Radar locates the plane at a distance D = 32 km from the dish, at an angle θ = 31° above horizontal. Part (a) What is the jet's horizontal distance, DH in meters, from the radar dish? DH 11114.5 DH = 1 1 110 V Correct! 33% Part (b) What is the jet's vertical distance, Dv in meters, above the radar dish?

A) Horizontal distance, DH= 27430 m

B) Vertical distance, DV= 16480 m

Explanation:

A) Horizontal distance, DH:

From the diagram, using SOHCAHTOA:

cosθ = adj/hyp

cos(31) = x/32

=> x = 32 * cos(31)

x = 27.43 km = 27430 m

Therefore, DH = 27430 m

B) VERTICAL DISTANCE, DV:

Using SOHCAHTOA:

sinθ = opp/hyp

sin(31) = x/32

= 32 * sin(31)

y = 16.48 km = 16480 m

Therefore, DV = 16480 m

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