A nonconducting sphere has radius R = 1.29 cm and uniformly distributed charge q = +3.83 fC. Take the electric potential at the sphere's center to be V0 = 0. What is V at radial distance from the center (a) r = 0.560 cm and (b) r = R? (Hint: See an expression for the electric field.)

a) -2.516 × 10⁻⁴ V

b) -1.33 × 10⁻³ V

Explanation:

The electric field inside the sphere can be expressed as:

The potential at a distance can be represented as:

V(r) - V(0) =

V(r) - V(0) = ₀

V(r) =   ₀

Given that:

q = +3.83 fc = 3.83 × 10⁻¹⁵ C

r = 0.56 cm

 = 0.56 × 10⁻² m

R = 1.29 cm

  =  1.29 × 10⁻² m

E₀ = 8.85 × 10⁻¹² F/m

Substituting our values; we have:

= -2.15  × 10⁻⁴ V

The difference between the radial distance  and center can be expressed as:

V(r) - V(0) =

V(r) - V(0) =  

V(r) =

V(r) =

V(r)

V(r) = -0.00133

V(r) = - 1.33 × 10⁻³ V

b

explanation:

grav force prop 1/r squared 2r all squared is 4rsquared 1/4rsquared quartered