In a wire with a 1.35 1.35 mm2 cross-sectional area, 5.41 × 10 20 5.41×1020 electrons flow past any point during 2.19 2.19 s. What is the current in the wire?

The current in the wire = 39.53 A.

Explanation:

The given cross -sectional area of the wire  = 1.35 .

The number of electrons flowing in the wire at any point is  

= 5.41 electrons.

The charge of an electron is known to be  =

The electronics flow across the wire for a time of, t = 2.19 seconds.

The current in the wire  = (number of electrons) ×

                                       = 5.41 ×

                                       =  39.53 A.

The formula for current is actually, i =  .  

The (number of electrons )×(charge of an electron) will equal the total charge flowing through the wire in the given time  = 2.19 seconds.

The current in the wire = 39.53 A.

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