(g)
1695 kJ of energy is transferred to water at 100 °C
The specific latent heat of vaporisation of water is 2.260 x 10 to the power of 6 J/kg
Calculate the mass of water changed into a gas at 100 °C
Mass of water =
kg

0.75kg

Explanation:

Q = mL

Where,  Q = quantity of heat

m= mass in kg

L = specific latent heat (J/kg)

Given,

Q= 1695KJ = 1695000J

mass (m)  = ?

L = 2.26×10"6 J/kg = 2260000J/kg

Q = mL

m = Q/L

m= 1695000 ÷ 2260000

m = 0.75kg

Mass = 0.75kg

Note: Specific latent heat of vaporization  is the quantity of heat required  to change a unit of mass of liquid to gaseous state at constant temperature (boiling point) and pressure

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are there options? cause you ain’t. real specific

2b2t

explanation:

2b2t