A 19.0 kg child is riding a playground merry-go-round that is rotating at 40.0 rev/min. What centripetal force (in N) must she exert to stay on if she is 2.00 m from its center

The centripetal force is 663.95 N.

Explanation:

Given that,

Mass of the child, m = 19 kg

Angular velocity of the merry-go-round,

Distance from the center, r = 2 m

We need to find the centripetal force acting on the child. The centripetal force is given by the formula as :

F = 663.95 N

So, the centripetal force is 663.95 N. Hence, this is the required solution.