A bicycle wheel with a radius of 0.42 m accelerates uniformly for 6.8 s from an initial angular velocity of 5.5 rad/s to a final angular velocity of 6.7 rad/s. What was its angular acceleration

The angular acceleration required  is 0.1765 rad/

Explanation:

The radius of the bicycle wheel has a radius of 0.42 m.

The acceleration is for time, t =  6.8 seconds.

Initial angular velocity is given as    = 5.5 rad/s

Final angular velocity is given as = 6.7 rad/s

Therefore from the formula for angular speed we get

= + ( t),   where t is the time in seconds.

Therefore we get

6.7 =  5.5 + (6.8 × )

Therefore we get the angular acceleration, =

The angular acceleration required  is 0.1765 rad/

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j