A Ferris wheel is a vertical, circular amusement ride with radius 7 m. Riders sit on seats that swivel to remain horizontal. The Ferris wheel rotates at a constant rate, going around once in 7 s.
Consider a rider whose mass is 52 kg.
At the bottom of the ride, what is the rate of change of the rider's momentum?

Change in momentum of the rider=803.4N

Explanation:

Fnet= mac

N- mg=mrw^2

N = mg + mrw^2

N = mg + mr (2×3.142/T)^2

Where T= period of revolutions

r = radius of ferris wheel

m= mass of rider

N= (52×9.8)+( 52×7)(2×3.142/7)^2

N=803.4N

answer; i believe the correct answer is (40,000 j) good luck

the temperature and the pressure affect solubility. temperature affects by changing the properties of the solvent. the increase in pressure increases solubility, the decrease in pressure decreases solubility.