A 2.0 kg wood block is launched up a wooden ramp that is inclined at a 30° angle. The block’s initial speed is 10 m/s. What vertical height does the block reach above its starting point? What speed does it have when it slides back down to its starting point?

Vertical Height = 0.784 meter, Speed back at starting point = 10 m/s

Explanation:

Given Data:

V is the overall velocity vector, and are its initial vertical and horizontal components

To find:

Max Height achieved

Calculation:

1) Using the equation of motion, we know

2) In terms of gravity height and  the vertical component of Velocity .

3) As as at maximum height the vertical component of velocity is zero maximum height achieved

putting values

4)

5) As for the speed when it reaches back its starting point, it will have a speed similar to its launching speed, the reason being the absence of air friction (Air drag)

a small object of mass 3.66 g and charge -17.6 µc is suspended motionless above the ground when immersed in a uniform electric field perpendicular to the ground. what are the magnitude and direction of the electric field?

talk back to him about the sport and show him your expertise or leave the room