Physics, 25.02.2020 04:56 Babyyygggirl26

Two asteroids begin to gravitationally attract one another. If one asteroid has twice the mass of the other, which one experiences the greater force? Which one experiences the greater acceleration?

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Answer from: Daniah2206

Forces are the same between the 2 but the lighter one would experience twice the acceleration

Explanation:

Newton's 3rd law states that action force on an object always results in an equal but opposite direction reaction force. In our case the gravitational force would be the same between the 2 asteroids. Their acceleration, however, is dictated by their mass according to Newton's 2nd law

F = ma

So with the same F, m and a is inversely proportional to each other. Therefore, if the lighter one has half the mass, its acceleration should be twice as much.

Answer from: ddmoorehouseov75lc

The forces experienced by the two asteroids are the same.

The asteroid with the smaller mass will have the greater acceleration. i.e it has twice the acceleration of the asteroid with the larger mass.

Explanation:

Newton's law of gravitation states that the force ( $F_{AB}$ ) exerted by an object of mass A ( $m_{A}$ ) on another object of mass B ( $m_{B}$ ) is the same as the force ( $F_{BA}$ ) exerted by the object of mass B on the object of mass A and also, this force is directly proportional to the product of the two masses and inversely proportional to the square of the distance (r) between these two masses. i.e

$F_{AB}$ = $F_{BA}$ = k $m_{A}$ $m_{B}$ / r² -----------------(i)

Now, to the question,

Let the mass of the first asteroid be $m_{A}$ and

the mass of the second asteroid be $m_{B}$ .

(a) The individual forces (F) experienced by the two asteroids are the same and will be given by;

F = k $m_{A}$ $m_{B}$ / r²

From the question,

$m_{A}$ = 2 x $m_{B}$

Substitute the value of $m_{A}$ = 2 x $m_{B}$ into equation (ii) as follows;

=> F = 2 k $m_{A}$ $m_{B}$ / r²

(b) Now, let's find the acceleration of each asteroid using Newton's second law of motion as follows;

F = m x a --------------------(iii)

Where;

F = force on the object

m = mass of the object

a = acceleration of the object

(i) To get the acceleration ( $a_{A}$ ) of the first asteroid, substitute:

m = $m_{A}$ = 2 x $m_{B}$ and;

a = $a_{A}$

into equation (iii) as follows;

F = 2 x $m_{B}$ x $a_{A}$

=> $a_{A}$ = F / (2 x $m_{B}$ ) ---------------(iv)

(i) To get the acceleration of the second asteroid ( $a_{B}$ ), substitute

m = $m_{B}$ and;

a = $a_{B}$

into equation (iii) as follows;

F = $m_{B}$ x $a_{B}$

=> $a_{B}$ = F / $m_{B}$ -----------------(v)

Since the forces on the two bodies are the same, lets divide equation (iv) by equation(v) as follows;

$\frac{a_{A} }{a_{B} }$ = $\frac{F / (2 * m_{B} )}{F / (m_{B} )}$

$\frac{a_{A} }{a_{B} }$ = $\frac{1}{2}$

$a_{B}$ = 2 x $a_{A}$

Therefore, the acceleration of the second asteroid is twice that of the first asteroid (the one with twice the mass of the first asteroid).

Answer from: Quest

Thesbrjd rubdfuhfbfux duvahavss

Answer from: Quest

v=ir = 3x15 =45 v

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