A 0.70 kg ball moving horizontally at 5.0 m/s strikes a vertical wall and rebounds with speed 2.0 m/s. What is the magnitude of the change in its linear momentum

4.9 kg.m/s.

Explanation:

Given that

mass ,m = 0.7 kg

Initial speed , u = 5 m/s ( Towards + x direction)

Final speed ,v= -2 m/s ( Towards - x direction)

We know that linear momentum is given as

P = Mass x velocity

Change in the linear momentum ΔP will be

ΔP = m ( v - u)

Now by putting the values in the above equation ,we get'

ΔP= 0.7 ( -2 - 5 )  kg.m/s

ΔP= - 4.9 kg.m/s

The magnitude of the change in the linear momentum will be 4.9 kg.m/s.

would be false hope this out

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.