Air enters a tank through a pipe with cross-sectional area of 0.2 ft2 with a velocity of 15 ft/s and a density of 0.03 slug/ft3 . Air leaves with a velocity of 5 ft/s and a density equal to that in the tank (which is homogeneously mixed). The initial density of the air in the tank is 0.02 slug/ft3 . The tank volume is 20 ft3 and cross-sectional area of the exit pipe is 0.4 ft2 . Find ��/�� at t = 0

he kicked it 10 feet straight up into the air? i think this works.

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.

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