How many joules are released as 10.0g of steam at 110℃ cools to produce water at 25℃?

26,000 J

Explanation:

Heat released when the steam is cooled:

q = mCΔT

q = (10.0 g) (2.02 J/g/K) (100℃ − 110℃)

q = -202 J

Heat released during condensation (gas to liquid):

q = mL

q = (10.0 g) (-2260 J/g)

q = -22,600 J

Heat released when the liquid water is cooled:

q = mCΔT

q = (10.0 g) (4.184 J/g/K) (25℃ − 100℃)

q = -3138 J

Total heat released:

q = -202 J − 22,600 J − 3138 J

q = 25,940 J

Rounded to two significant figures, 26,000 J of heat are released.

i had this question and the answer was 3.15 miles.

martina travels from school to her mom's office. from there, she walks to school. after school, she walks to the library and then to a friends house before finally ending back at home. find martina's total distance traveled.

a) 0 miles  

b) 0.4 miles  

c) 1 mile  

d) 3.15 miles