A 5 kg cannon ball is loaded into a 300 kg cannon. When the cannon is fired, it recoils at -5 m/s. What is the cannon ball's velocity after the explosion?

300m/s

Explanation:

The principle of conservation of linear momentum applies to this problem. The total momentum before explosion is equal to the total momentum after the explosion.

Let the mass of the cannon be and the mass of the ball be .  According to the principle of conservation of linear momentum the following relationship holds;

Since both bodies are at rest before the explosion their initial velocities are zero; and . Equation (1) then reduces to

Which means that,

Given;

Substituting all values into equation (3), we obtain the following;

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation: