A small .40 kg cart is moving back and forth along an air track between two bumpers that are 2 m apart on the air track with a constant speed of .50m/s by treating the cart as a quantum particle, estimate the value of the principle quantum number that corresponds to its classical energy

Wavelength divides in half and speed stays the same.

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

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