Find the electric field inside a hollow plastic ball of radius R that has charge Q uniformly distributed on its outer surface. Give your answer as a multiple of Q/ε0.Express your answer in terms of some or all of the variables R, r and the constant π.

The electric field inside the hollow plastic ball is zero.

Explanation:

According to Gauss's law, the electric field at the closed Gaussian surface is given by

Now, to find the electric field inside the hollow plastic ball, we choose a spherical Gaussian surface inside the ball. And since all of the charge lies on the surface of the ball, the Gaussian surface does not enclose any charge; therefore, the Gauss's law gives:

The electric field inside the hollow plastic ball is zero.

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.

wavelength divides in half and speed stays the same.