A car with a mass of 860 kg sits at the top of a 32 meter high hill. Describe the transformations between potential and kinetic energy that occur when the car rolls to the bottom of the hill and continues rolling.

Kinetic energy at the bottom equals potential energy at the top hence 269971.2  J

Explanation:

Assuming no friction and neglecting air resistance, from the law of conservation of energy, the potential energy that the car posses at 32 m is all converted to kinetic energy hence

PE= mgh

Here m denotes the mass of the car, g is acceleration due to gravity, h is the height and v is the speed of the car

The potential energy will be PE= 860*9.81*32=269971.2  J

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form