Two forces whose resultant is 100N, are perpendicular to each other. if one of them makes an angle of 60° with the resultant, calculate it's magnitude

Calculate the absolute pressure of an ocean depth of 1200atm. Assuming the density of liquid is 1200kg/m^2amd that (pa=1.01×10^6pa N/m^2

Magnitude of the force = 50N

Explanation:

Let one force be X

And the second force be Y

Both the forces are perpendicular, so α = 90°

The resultant R of the two forces = 100N

Angle between resultant and 1 force, α = 60°

We know,

R² = X² + Y² + 2XYcos 90

100² = X² + Y²

If X makes an angle of Φ = 60°

Then, tan Ф =  Y sin α / X + Y cos α

Putting the values we find,

tan 60 = Y/X

Y  = √3X

Putting Y = √3X in equation 1 we get,

(X)² + (√3X)² = 100 X 100

4X² = 100 X 100

X² = 2500

X = 50N

Therefore, magnitude of the force = 50N

im guessing the west of station b