Question 3 An molecule adsorbed at one site on a surface. An oxygen molecule is adsorbed onto a small patch of the surface of a catalyst. It's known that the molecule is adsorbed on of possible sites for adsorption (see sketch at right). Calculate the entropy of this system. Round your answer to

The question has some details missing. Here is the complete question ; An molecule adsorbed at one site on a surface. An oxygen molecule is adsorbed onto a small patch of the surface of a catalyst. It's known that the molecule is adsorbed on 1 of 576 possible sites for adsorption (see sketch at right). Calculate the entropy of this system. Round your answer to 3 significant digits.

Explanation:

The stefan boltzmaan constant for entropy is given by ;

S = kInwwe are given that 576 total possible sites in which O2 can get absorbedw = 576, k = 1.38 x 10-23J/k

plugging the values into the equation ;

S = 1.38 x 10-23J/k X In(576)

Entropy of the system = 8.79 X 10-23J/k

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

Ohm's law tells you that i = v/r where v is equivalent voltage and r is equivalent resistance of the circuit
since all circuits have the same voltage, your question is really asking which circuit has the lowest total resistance, since the lower the resistance, the higher the current
circuit a has a resistance of 5 ohms; circuit c is in series so has a resistance of 10 ohms; circuit b is in parallel and therefore has a resistance of 2.5 ohms (review your notes on adding resistances in parallel and series); therefore b has the highest current