A 26.0 kg kg crate is initially moving with a velocity that has magnitude 3.75 m/s m/s in a direction 37.0 ∘ ∘ west of north. 1. How much work must be done on the crate to change its velocity to 5.31 m/s m/s in a direction 63.0 ∘ ∘ south of east? 2. Express your answer to three significant figures and include the appropriate unit.

184 J

Explanation:

We are given that

Mass of crate=26 kg

Initial velocity=u=3.75 m/s

Direction= W of N

Final velocity=v=5.31 m/s

Direction=S of E

We have to find the work done on the crate to change its velocity.

By using work energy theorem

Work done=Change in kinetic energy

Work done=

Work done=

Work done=367 J-183 J=184 J

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