A dart is thrown horizontally with an initial speed of 16 m/s toward point P, the bull’s-eye on a dart board. It hits at point Q on the rim, vertically below P, 0.19 s later. What is the distance P Q?

0.18 m

Explanation:

The motion of the dart comprises horizontal and vertical components. Vertically, the initial velocity is 0 because the dart was thrown horizontally. Also, the vertical motion is under gravity. Using the equation of motion

where is the vertical distance from P, is the initial velocity, is the acceleration and is time, we have

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.