A uniform electric field of magnitude 6.8 105 N/C points in the positive x-direction. Find the change in electric potential (?V) between the origin and each of the points given below.
(a) (0, 5.0 m)
V

(b) (5.0 m, 0)
V

(c) (5.0 m, 5.0 m)
V

Solution:

Substitute the values in the formula V=-E*d we get the answers

let us consider the electric field  that travels in a positive way or the positive direction and E denotes the magnitude

Where E= 6.8 10^5 N/C

We have the formula, V=-E*d

Take d value as 5 from the option  one

put V=0 since the fields are in the  X direction and the points are in the Y direction

By the formula,

(0, 5.0 m)

V=-E*d

V= -6.8x10^5V/m*5m

V=-3.40x10^6V

By the formula (5.0 m, 0)

V=-E*d

V= -6.8x10^5V/m*5m

V=-3.40x10^6V

By the formula ,

(5.0 m, 5.0 m)

V=-E*d

V= -6.8x10^5V/m*5m

V=-3.40x10^6V

sub V=5 we get,

V=-3.40x10^6V+5

v=2.40x10^6V

tbh i dont know ether

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.