A defibrillator passes 14.29 A of current through the torso of a person for 8 ms. How much charge moves (in Coulombs)

q=0.11432 C

Explanation:

Given that

Current ,I= 14.29 A

Time ,t= 8 ms= 8 x 10⁻³ s

We know that ,The relationship between current and time is given as

t=time

q=Charge

I=Current

q= I t

Now by putting the values in the above equation we get

q= 14.29 x 8 x 10⁻³

q=114.32 x 10⁻³  C

q=0.11432 C

Therefore the charge will be 0.11432 C.

the answer is a)

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