A 5.5 kg box is pushed across the lunch table. the net force applied to the box is 9.7 N. what is the acceleration of the box?

1.76m/s²

Explanation:

Acceleration is the time rate of change in velocity of a body. It is a vector quantity that is it has both magnitude and direction

From newton's second law of motion which states that the rate of change of momentum of a body is proportional to the applied force which takes place in the direction of force applied.

This law gives a formula which relate force, mass and acceleration.

Force = mass x acceleration

Given that force = 9.7N , mass = 5.5kg

Since force(F)= mass(m) x acceleration(a)

Therefore F = ma

Divide both sides by m

F/m = ma/m

Therefore,

Acceleration (a)  = F/m

Acceleration = 9.7N ➗ 5.5kg

Acceleration = 1.76m/s²

The S. I unit of acceleration is m/s²

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representative si the final answer! : )

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