009 10.0 points

Find the density of seawater at a depth where

the pressure is 360 atm if the density at the

surface is 1045 kg/m'. Seawater has a bulk

modulus of 2.3 x 10' N/m". Bulk modulus is

defined to be

B = PAP

Ap

Explanation:

Bulk modulus (B) =  2.3 x 10⁹ N/m²

B = Δp/ (Δv/v)

Δp = B (Δv/v)

density = mass / volume

d = m/ v

ln d = ln m - ln v

Δd/d = -Δv/v

Δp = B (Δd/d)

Δp = 360 - 1 = 359 atom

= 359 x 10⁵ N/m²

359 x 10⁵ =2.3 x 10⁹ x (Δd/d)

Δd = (359 x 10⁵/ 2.3 x 10⁹) x d

= 156.08 x 10⁻⁴ x 1045

= 16.31 kg/m³

increased density

= 1045 +16.31

= 1061.31 kg/m³

=

The density of seawater at a depth is 1061.3 kg/m³.

Explanation:

Given that,

Pressure = 360 atm

Density at the surface = 1045 kg/m³

Bulk modulus

We need to calculate the density of seawater at a depth

Using formula of density

Put the value into the formula

Hence, The density of seawater at a depth is 1061.3 kg/m³.

i agree kid

explanation:

a

luster is not a good characteristic to use by itself because luster is the property of minerals that indicates how much the surface of a mineral reflects light. the luster of a mineral is affected by the brilliance of the light used to observe the mineral surface.