Determine the maximum potential difference that can be applied to a Teflon-filled parallel-plate capacitor having a plate area of 2.00 cm2 and a plate separation of 0.020 0 mm.

1200V

Explanation:

A = 2.0cm2 = 0.0002m2

d = 0.0200mm = 0.00002m

Dielectric strength of Extruded Teflon is 6x107 V/m = Em,

so, maximum voltage = Em * d = 6x107 V/m x 0.00002 m = 1.2x103 V = 1200 V

they should be similar or the same

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg