We are sending a 30 Mbit file from source host A to destination host B. All links in the path between source and destination have a transmission rate of 10 Mbps. Assume that the propagation speed is 2 *10^8 meters/sec, and the distance between source and destination is 10,000 km. The end-to-end delay (transmission delay plus propagation delay) is:

Explanation:

Given:

Now the delay in data transfer from source to destination for each 10 Mb:

Now this time is taken for each 10 Mb of data transfer and we have 30 Mb to transfer:

So,

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explanation: