Physics, 19.02.2020 20:45 eparikh7317

Electric Potential and Potential Energy

A particle with charge 8.00×10−19 C is placed on the xaxis in a region where the electric potential due to other charges increases in the +x direction but does not change in the y or z direction.

Part A

The particle, initially at rest, is acted upon only by the electric force and moves from point a to point b along the x axis, increasing its kinetic energy by 9.60×10−19 J . In what direction and through what potential difference Vb−Va does the particle move?

The particle, initially at rest, is acted upon only by the electric force and moves from point a to point b along the x axis, increasing its kinetic energy by 9.60×10−19 . In what direction and through what potential difference does the particle move?

The particle moves to the left through a potential difference of Vb−Va= 1.20 V .
The particle moves to the left through a potential difference of Vb−Va= -1.20 V
The particle moves to the right through a potential difference of Vb−Va= 1.20 V .
The particle moves to the right through a potential difference of Vb−Va= -1.20 V .
The particle moves to the left through a potential difference of Vb−Va= 12.0 V .
The particle moves to the right through a potential difference of Vb−Va= -12.0 V .
Part B

If the particle moves from point b to point c in the y direction, what is the change in its potential energy, Uc−Ub?

If the particle moves from point b to point c in the y direction, what is the change in its potential energy, ?

+ 9.60×10−19 J
− 9.60×10−19 J
0

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Answer from: Quest

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

$f\alpha \frac{dp}{dt}$

⇒ $f= k \frac{dp}{dt}$

here k is the proportionality constant whose value is 1.

$f=\frac{dp}{dt}$

$f= \frac{d[mv]}{dt}$

$f= m\frac{dv}{dt} +v\frac{dm}{dt}$

$f=ma+v\frac{dm}{dt}$ [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.

Answer from: Quest

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2

Answer from: Quest

it's when something is going so fast it makes a loud noise, breaking the sound barrier, for example: a jet makes a loud noise, not only cause of the jet but because they reached a point where they went so fast that you can year the noise from various parts, kinda like a police car, lets say the car was going so fast that you hear the siren of the cop car right next to you, but the car is probably a mile a way, it's cos the siren was next to you a few seconds if you understand me

Answer from: Quest

The best description is: . nobody has any idea what q is.

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Electric Potential and Potential Energy

A particle with charge 8.00×10−19 C is placed on...

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