A spherical conductor of radius 15.5 cm has net charge

Q = 0.66 µC.

Calculate the electric potential at the following distances from its center, assuming the electric potential goes to zero at an infinite distance from the sphere.

A spherical conductor of radius 15.5 cm

the electric potential in the sphere is 3.88 X 10⁴ Volts

Explanation:

Electric potential is given as;

V = kq/r

where;

q is the charge present in the sphere = 0.66 µC

k is coulomb's constant = 8.99 X 10⁹ C

r is the radius of the sphere = 15.5 cm = 0.155 m

V = (8.99 X 10⁹  * 0.66 X 10⁻⁶)/0.155

V = 3.88 X 10⁴ Volts

Therefore, the electric potential in the sphere is 3.88 X 10⁴ Volts

The electric potential in the sphere is 3.9 X 10⁴ V.

Explanation:

Electric potential, V = kq/r

where,

q = charge

= 0.66 µC

k = coulomb's constant

= 8.99 X 10⁹ C

r = radius of the sphere

= 15.5 cm

= 0.155 m

V = (8.99 X 10⁹  * 0.66 X 10⁻⁶)/0.155

= 3.9 X 10⁴ V.

answer: he got 23

explanation:

photocells convert light energy to electricity