Points A and B are in a region of uniform electric field. Point A is at the origin and point B is on the x-axis at x = 0.150 m. The electric potential at point A is 200 v and the electric potential at point B is 500 v. What are the magnitude and direction of the uniform field in this region?

2000 v/m, from B to A.

Explanation: if point A is at the origin (x=0m) and point B is at the point x= 0.150m, the distance between both points (d) = 0.150 - 0 = 0.150m

Point A is at a 200v potential and point B is at a potential of 500v.

Difference in potential produces a voltage (v) = 500 - 200 = 300v.

The relationship between voltage, electric field intensity and distance is given by the formulae below

v=Ed

Where v = voltage = 300v, electric field =?, d = 0.150m

300 = E×0.150

E = 300/0.150

E = 2000 v/m.

Since point B is at higher potential than A, it implies that if there is an electron in this field, it will move from B to A thus making the direction of field be from B to A.

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as we know our atmosphere or air have different levels. every level has other gasses, and every gas has another permeability. when the light comes from lower permeability to higher permeability, it changes its direction. so that means that when the light comes from the moon to the earth, it changes it's direction many more times. it basically means that the shape of the light part of the moon is changed on the earth.

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