If 1.4% of the mass of a human body is calcium, how many kilograms of calcium are there in a 195-pound man?

1.241 kg

Explanation:

The mass of the man in kg is 195 pound * (1/2.2) kg/pound = 195/2.2 = 88.64 kg

If 1.4% of the mass of a human body is calcium, then the mass of calcium inside the 88.64 kg man is

1.4% * 88.64 = 88.64*1.4/100 = 1.241 kg

So there's 1.241 kg of calcium inside a 195-pound man

1.24kg

Given;

Mass of the man (M) = 195 pound

First, convert the value to kilograms (kg) as follows;

Note that;

1 pound = 0.453592kg

Therefore,

195 pounds = 195 x 0.453592kg =  88.45kg

Now, since the mass of calcium (say m) in a human body is 1.4% of the mass (M) of the body;

=> m = 1.4% of M

=> m = 1.4% x M (i)

Where;

M = 88.45kg

Substitute the value of M into equation (i) as follows;

=> m = 1.4 % x 88.45

=> m = (1.4 / 100) x 88.45

Solve for m;

m = 0.014 x 88.45

m = 1.24kg

Therefore, the mass of calcium in the 195-pound man is 1.24kg.

what was the answer?

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.