Physics, 18.02.2020 02:14 bearbri4520

Water at 65 oF and 20 psia is heated in a chamber by mixing it with saturated water vapor at 20 psia. If both streams enter the mixing chamber at the same mass flow rate, determine the temperature and the quality of the exiting stream.

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Answer from: arianna23717

Explanation:

Equation for mass balance is as follows.

$\Delta m_{system} = m_{in} - m_{out} = 0$

$m_{in} = m_{out}$

$m_{1} + m_{2} = m_{3} = 2m$ .......... (1)

$m_{1} = m_{2} = m$

Equation for energy balance is as follows.

$E_{in} - E_{out} = \Delta E = 0$

$E_{in} = E_{out}$

Hence, $m_{1}h_{1} + m_{2}h_{2} = m_{3}h_{3}$ ......... (2)

When we combine both equations (1) an d(2) will be as follows.

$m_{1}h_{1} + m_{2}h_{2} = 2mh_{3}$

or, $h_{3} = \frac{(h_{1} + h_{2})}{2}$

Hence, putting the given values into the above equation as follows.

$h_{3} = \frac{(h_{1} + h_{2})}{2}$

$h_{3} = \frac{(33.08 + 1156.2)}{2}$

= 594.6 Btu/lbm

Therefore, $T_{3} = T_{sat 20psi} = 228^{o}F$

And, $x_{3} = \frac{h_{3} - h_{f}}{h_{fg}}$

= $\frac{594.6 - 196.27}{1156.2 - 196.27}$

= 0.415

Answer from: Quest

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm. the wire diameter is d = 0.9 mm. the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2) in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation:

Answer from: Quest

the grams of oxygen gas that can be produced is 20.6 grams of o₂

calculation

2liclo₃ → 2 licl + 3 o₂

step 1: find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5 +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281 moles

step 2: use the mole ratio to calculate the moles of o2

from equation above, liclo₃: o₂ is 2: 3

therefore the moles of o₂=0.4281 moles x3/2 =0.6422 moles

step 3: find mass of o₂

mass= moles x molar mass

from periodic table the molar mass of o₂ = 16 x2= 32 g/mol

mass=0.6422 moles x 32 g/mol = 20.6 grams of o₂

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