A test car starts from rest on a horizontal circular track of 85-m radius and increases its speed at a uniform rate to reach 115 km/h in 13 seconds. Determine the magnitude a of the total acceleration of the car 11 seconds after the start.

27.03 m/s.

Explanation:

vo = 0 m/s

vi = 115 km/h

Converting to m/s,

115 km/h * 1000 m/1 km * 1 h/3600 s

= 31.94 m/s.

Using equation of motion,

vi = vo + at

a = 31.94/13

= 2.46 m/s^2

After t = 11 s,

vi = 2.46 * 11

= 27.03 m/s.

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