Explain why the work needed to move a particle with charge Q through a potential difference ΔV is W = QΔV, whereas the energy stored in a charged capacitor is = ∆. Where does the factor 1 2 come from?

Question:Explain why the work needed to move a particle with charge Q through a potential difference ΔV is W = QΔV, whereas the energy stored in a charged capacitor is U= 1/2Q∆V. Where does the factor 1/2 come from?

When we move a single charge q through a potential difference ∆v, its potential energy changes by qΔV.

Charging a capacitor involves moving a large number of charges from one capacitor plate to another. If ∆V is the final potential difference on the capacitor, and Q is the magnitude of the charge on each plate, the energy stored in the capacitor is

U = 1/2 Q∆V.

The factor of 1/2 is because, on average, the charges were moved through a potential difference of ½∆v

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.