An automobile accelerates from rest at 2.3 m/s2 for 16.2 s. The speed is then held constant for 18.4 s, after which there is an acceleration of -2.5 m/s2 until the automobile stops. What is the total distance traveled

Explanation:

Given

For first part acceleration is

time

distance traveled is given by

where s=displacement

u=initial velocity

a=acceleration

t=time

For second part speed acquired is held constant for

Distance traveled during this time

For the last part it decelerate with until the car stops so

distance moved in last part is given by

here

Total distance

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

lol

explanation: