A student decides to measure the muzzle velocity of a pellet from his gun. He points the gun horizontally. He places a target on a vertical wall a distance 3.27 m away from the gun. The pellet hits the target a vertical distance 0.264 m below the gun. What is the speed of the pellet?

8.36 m/sec

Explanation:

Since muzzel velocity is required to be determined i-e velocity with which bullet leaves the gun. So we have to suppose that bullet has no acceleration and moves with constant velocity.

a=0 m/sec2

Vi=0 (initially the bullet is at rest)

S= 3.27 m

using m/s

S= Vit+1/2at2

==> 3.27 = 0+0.5×

==> = 6.54

==> t=2.56 sec

Now using S= V×t

==> V = S/t

==> V= 3.27 × 2.56 = 8.36 m/sec

area of focus

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.